openLinkInApp function

Future<void> openLinkInApp(
  1. BuildContext context,
  2. String url
)

打开链接：支持端内 WebView 的平台用半屏；否则 url_launcher 外开。

Implementation

Future<void> openLinkInApp(BuildContext context, String url) async {
  final normalized = normalizeHttpUrl(url) ?? url;
  await openHttpUrl(
    normalized,
    context: context,
    preferInAppWebView: PlatformCapabilities.supportsInAppWebView,
  );
}