GoogleDriveSource.fromJson constructor

GoogleDriveSource.fromJson(
  1. Object? j
)

Implementation

factory GoogleDriveSource.fromJson(Object? j) {
  final json = j as Map<String, Object?>;
  return GoogleDriveSource(
    resourceIds: switch (json['resourceIds']) {
      null => [],
      List<Object?> $1 => [
        for (final i in $1) GoogleDriveSource_ResourceId.fromJson(i),
      ],
      _ => throw const FormatException('"resourceIds" is not a list'),
    },
  );
}