indexOf method

  1. @override
int indexOf(
  1. Object? element, [
  2. int start = 0
])
override

The first index of element in this list.

Searches the list from index start to the end of the list. The first time an object o is encountered so that o == element, the index of o is returned.

final notes = <String>['do', 're', 'mi', 're'];
print(notes.indexOf('re')); // 1

final indexWithStart = notes.indexOf('re', 2); // 3

Returns -1 if element is not found.

final notes = <String>['do', 're', 'mi', 're'];
final index = notes.indexOf('fa'); // -1

Implementation

@override
int indexOf(Object? element, [int start = 0]) {
  if (start < 0 || start >= _length && _length > 0) {
    return -1;
  }
  _Node<E>? current = _getNodeAt(start);
  for (int i = start; i < _length; i++) {
    if (current!.value == element) {
      return i;
    }
    current = current.next;
  }
  return -1;
}