show method

Future<void> show({
  1. required BuildContext context,
  2. required String screen,
  3. Config? config,
  4. String? type,
})

Implementation

Future<void> show({
  required BuildContext context,
  required String screen,
  Config? config,
  String? type,
}) async {
  throw UnimplementedError('show() has not been implemented.');
}